2024-heraklion-testing-debu.../hands_on_solutions/local_maxima_part3_debug/local_maxima_solution.py
2024-08-26 13:54:13 +02:00

68 lines
1.6 KiB
Python

import math
import numpy as np
def find_maxima(x):
"""Find local maxima of x.
Input arguments:
x -- 1D list of real numbers
Output:
idx -- list of indices of the local maxima in x
"""
maxima = []
len_x = len(x)
if len_x == 0:
return maxima
elif len_x == 1:
return [0]
# additional checks
if np.all([isinstance(item, str) for item in x]):
x = [item.lower() for item in x]
if np.all([item == x[0] for item in x]):
return [0]
maxima = check_first_element(x, maxima)
# Check numbers in between
i = 1
while i < len_x - 1:
if x[i] >= x[i - 1]:
# We have found a potential maximum or start of a plateau
# breakpoint()
if i == 1 and x[i] == x[i - 1]:
plateau_start = i - 1
else:
plateau_start = i
while i < len_x - 1 and x[i] == x[i + 1]:
i += 1
plateau_end = i
if plateau_end == len_x - 1:
maxima.append((plateau_end + plateau_start) // 2)
elif x[plateau_end] > x[plateau_end + 1]:
maxima.append((plateau_end + plateau_start) // 2)
i += 1
maxima = check_last_element(x, maxima)
return maxima
def check_first_element(x, maxima):
if x[0] > x[1]:
maxima.append(0)
return maxima
def check_last_element(x, maxima):
if x[-1] > x[-2]:
maxima.append(len(x) - 1)
return maxima
if __name__ == "__main__":
# result = find_maxima([1, 3, -2, 0, 2, 1])
result = find_maxima([1, 2, 2, 1])
print(result)